AP+Review+7+Question+13

Review 7, Question 13- A particle moves along the y-axis so that its velocity v at time t > 0 is given by v(t)=1-tan^(-1)(e^(t)). At time t=0, the particle is at y=-1. (Note: tan^(-1)(x)= arctan(x) a. Find the acceleration of the particle at time t= 2. b. Is the speed of the particle increasing or decreasing at time t= 2? Give a reason for your answer. c. Find the time t > ) at which the particle reaches is highest point. Justify your answer. d. Find the position of the particle at time t= 2. Is the particle moving toward the origin or away from the origin at time t= 2? Justify your answer. Kelly Ancharski